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NEW QUESTION: 1
You have flown to NYC to have a discussion with a technical executive of a too big to fail bank. You are having a discussion about blockchain algos and the customer is asking what are some disadvantages of using a POW algo?
A. Not profitable for miners
B. Centralization of blockchain control
C. Large expenditures for computational power
D. Only use case for computational power is blockchain
E. 51% attack mitigation
Answer: C,E
Explanation:
Explanation/Reference:
Explanation:
The main disadvantages are huge expenditures, "uselessness" of computations and 51 percent attack.
Reference: https://cointelegraph.com/explained/proof-of-work-explained
NEW QUESTION: 2
Given the code fragment:
System.out.printIn("Result: " + 2 + 3 + 5);
System.out.printIn("Result: " + 2 + 3 * 5);
What is the result?
A. Result: 215
Result: 215
B. Compilation fails
C. Result: 10
Result: 25
D. Result: 235
Result: 215
E. Result: 10
Result: 30
Answer: D
Explanation:
Explanation/Reference:
Explanation:
First line:
System.out.println("Result: " + 2 + 3 + 5);
String concatenation is produced.
Second line:
System.out.println("Result: " + 2 + 3 * 5);
3*5 is calculated to 15 and is appended to string 2. Result 215.
The output is:
Result: 235
Result: 215
Note #1:
To produce an arithmetic result, the following code would have to be used:
System.out.println("Result: " + (2 + 3 + 5));
System.out.println("Result: " + (2 + 1 * 5));
run:
Result: 10
Result: 7
Note #2:
If the code was as follows:
System.out.println("Result: " + 2 + 3 + 5");
System.out.println("Result: " + 2 + 1 * 5");
The compilation would fail. There is an unclosed string literal, 5", on each line.
NEW QUESTION: 3
キーのインポートまたはエクスポート中にパスフレーズ保護を提供する暗号化方法はどれですか？
A. AES
B. RSA
C. フグ
D. 蛇
Answer: B
Explanation:
参照：
https://www.cisco.com/c/en/us/td/docs/ios-xml/ios/sec_conn_pki/configuration/xe-3s/sec-pki-xe-3sbook/sec-dep
NEW QUESTION: 4
A. Option C
B. Option A
C. Option D
D. Option B
Answer: A