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NEW QUESTION: 1
식당 예약 애플리케이션에는 대기자 명단을 유지하는 기능이 필요합니다. 고객이 테이블을 예약하려고 하는데 사용 가능한 테이블이 없으면 고객을 대기자 명단에 올려야 하며 테이블이 비어있을 때 응용 프로그램이 고객에게 알려야합니다.
시스템이 고객 요청이 대기자 명단에 올라간 순서를 존중하도록 Solutions Architect는 어떤 서비스를 권장해야 합니까?
A. Amazon SNS
B. Amazon SQS의 FIFO 대기열
C. 순차적 디스패치 기능이있는 AWS Lambda
D. Amazon SQS의 표준 대기열
Answer: B
Explanation:
Explanation
https://aws.amazon.com/about-aws/whats-new/2019/02/amazon-sqs-fifo-qeues-now-available-in-15-aws-region
NEW QUESTION: 2
To change the name of your Quidway router to myrouter, which command should be input?
A. [Quidway]name myrouter
B. [Quidway]hostname myrouter
C. [Quidway]sysname myrouter
D. [Quidway]host myrouter
Answer: C
NEW QUESTION: 3
In WebLogic, the development feature to automatically load/refresh the changes of a Java classes at run time is called__________.
A. FastSwap
B. HotSwap
C. FastReload
D. HotDeploy
E. FastDeploy
Answer: A
Explanation:
Explanation/Reference:
Using FastSwap Deployment to Minimize Redeployment
Java EE 5 introduces the ability to redefine a class at runtime without dropping its ClassLoader or abandoning existing instances. This allows containers to reload altered classes without disturbing running applications, vastly speeding up iterative development cycles and improving the overall development and testing experiences. The usefulness of the Java EE dynamic class redefinition is severely curtailed, however, by the restriction that the shape of the class - its declared fields and methods - cannot change.
The purpose of FastSwap is to remove this restriction in WLS, allowing the dynamic redefinition of classes with new shapes to facilitate iterative development.
With FastSwap, Java classes are redefined in-place without reloading the ClassLoader, thereby having the decided advantage of fast turnaround times. This means that you do not have to wait for an application to redeploy and then navigate back to wherever you were in the Web page flow. Instead, you can make your changes, auto compile, and then see the effects immediately.
Reference: Using FastSwap Deployment to Minimize Redeployment
NEW QUESTION: 4
Which two commands would help you troubleshoot a LUN that cannot be accessed by a host? (Choose two.)
A. fcp show wwpn
B. igroup show
C. lun show -err
D. lun show -v
E. fcp wwpn
Answer: B,D
Explanation:
https://library.netapp.com/ecmdocs/ECMP1196979/html/man1/na_igroup.1.html
igroup show [ -v ] [ initiator_group ] Displays the nodes in an initiator group and their aliases, set
with the fcp wwpnalias command. If no initiator_group is specified, the members of all initiator
groups are displayed. You can use the -v option to get a verbose listing.
https://library.netapp.com/ecmdocs/ECMP1196979/html/man1/na_lun.1.html
lun show [ -v | -m | -c ] [ all | mapped | offline | online | unmapped | staging |
-g initiator_group | -n node | -l vol_name | lun_path ] Displays the status (lun_path, size,
online/offline state, shared state) of the given LUN or class of LUNs. With the -v option supplied,
additional information (comment string, serial number, LUN mapping, HA Pair Shared Volume
Information) is also displayed. With the -m option supplied, information about lun_path to
initiator_group mappings is displayed in a table format. With the -c option supplied, information
about LUN cloning status is displayed.