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NEW QUESTION: 1
A user is configuring MySQL RDS with PIOPS. What should be the minimum size of DB storage provided by the user?
A. 50 GB
B. 1 TB
C. 5 GB
D. 100 GB
Answer: D
Explanation:
If the user is trying to enable PIOPS with MySQL RDS, the minimum size of storage should be
100 GB.
http://docs.aws.amazon.com/AmazonRDS/latest/UserGuide/USER_PIOPS.html
NEW QUESTION: 2
-- Exhibit -
{master:0}[edit]
user@router# show class-of-service
classifiers {
inet-precedence normal-traffic {
forwarding-class best-effort {
loss-priority low code-points [ my1 my2 ]; } }
}
code-point-aliases { inet-precedence { my1 000; my2 001; }
}
scheduler-maps { one { forwarding-class expedited-forwarding scheduler special; forwarding-class best-effort scheduler normal; }
}
schedulers { special { transmit-rate percent 30; priority strict-high; } normal { transmit-rate percent 70; priority low; }
} -- Exhibit -Click the Exhibit button.
The configuration in the exhibit shows incoming traffic with specific IP precedence bits that should be mapped to a forwarding class named best-effort.
What must you add to complete this configuration?
A. a WRED drop-profile for the best-effort scheduler
B. defined behaviors to the interfaces stanza in the class-of-service section
C. rewrite-rules for the best-effort forwarding class
D. a firewall filter that matches and discards the original code point values
Answer: B
NEW QUESTION: 3
Which Guiding principle says that it is not usually necessary to build something new?
A. Focus on value
B. Think and work holistically
C. start where you are
D. Progress iteratively with feedback
Answer: C
NEW QUESTION: 4
You have a database that contains the following tables:
You need to write a query that returns a list of all customers who have not placed orders.
Which Transact-SQL statement should you run?
A. SELECT c.custid FROM Sales.Customers c INNER JOIN Sales.Order oON c.custid = o.custid
B. SELECT custid FROM Sales.Customers INTERSECTSELECT custid FROM Sales.Orders
C. SELECT c.custid FROM Sales.Customers c RIGHT OUTER JOIN Sales.Orders o ON c.custid = o.custid
D. SELECT custid FROM Sales.Customers UNION ALL SELECT custid FROM Sales.Orders
E. SELECTc.custid FROM Sales.Customers c LEFT OUTER Sales.Order oON c.custid = o.custid
F. SELECT custid FROM Sales.Customers UNION SELECT custid FROM Sales.Orders
G. SELECT c.custid FROM Sales.Customers c LEFT OUTER JOIN Sales.Order oON c.custid = o.custid WHERE orderid IS NULL
Answer: G
Explanation:
Explanation/Reference:
Explanation:
Inner joins return rows only when there is at least one row from both tables that matches the join condition.
Inner joins eliminate the rows that do not match with a row from the other table. Outer joins, however, return all rows from at least one of the tables or views mentioned in the FROM clause, as long as those rows meet any WHERE or HAVING search conditions. All rows are retrieved from the left table referenced with a left outer join, and all rows from the right table referenced in a right outer join. All rows from both tables are returned in a full outer join.
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx