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NEW QUESTION: 1
ホットスポット-HSRP
Ferris Plastics、Inc.は、ユーザーPCから企業サーバーへのLAN接続を提供するエンタープライズネットワーク(アクセス、ディストリビューション、コアスイッチ)を備えた中規模企業です。ディストリビューションスイッチは、HSRPを使用して高可用性ソリューションを提供するように構成されています。
-DSW1-VLAN 101 VLAN 102およびVLAN 105のプライマリデバイス
-DSW2-VLAN 103およびVLAN 104のプライマリデバイス
-プライマリデバイスでGigabitEthemet1 / 0/1に障害が発生すると、
プライマリデバイスとしてのステータスを解放するプライマリデバイス
バックアップデバイスのGigabitEthernet1 / 0/1も失敗しました。
トラブルシューティングにより、いくつかの問題が特定されました。現在、すべてのインターフェースが稼働しています。実行コンフィギュレーションとshowコマンドを使用して、次の質問を調査して回答するように求められました。
Dumps NSE7_LED-7.0 PDF
すべてのインターフェースがアクティブです。 DSW2は、VLAN 103 HSRPグループのアクティブデバイスになっていません。
VLAN 103 HSRPグループに関連して、グループを適切に機能させるために何ができますか?
A. DSW1で、優先度の値を190未満で150を超える値に下げます。
B. DSW2では、優先度の値を200より大きく250より小さい値に増やします。
C. DSW1で、プリエンプトを無効にします。
D. DSW2で、trackコマンドのデクリメント値を10より大きく、50より小さい値に増やします。
Answer: B
Explanation:
From the output shown below of the HSRP status of DSW2, we see that the active router has a priority of 200, while the local priority is 190. We need to increase the priority of DSW2 to greater than 200, but it should be less than 250 so that if the gig 1/0/1 interface goes down, DSW1 will become active. DSW2 is configured to decrement the priority by 50 if this interface goes down, so the correct answer is to increase the priority to more than 200, but less than 250.
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NEW QUESTION: 2
How can you display the contents of a hidden folder on a mounted volume in Finder?
A. From the Go menu, choose "Go to Folder," enter the path to the hidden folder, and click Go.
B. From the View menu, choose "Show hidden items."
C. From the Finder menu, choose Preferences, and select "Show hidden items."
D. Select the volume icon and choose "Show hidden items" from the Action menu.
Answer: A

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <algorithm>
#include <vector>
#include <set>
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int main() {
vector<int> v1(10,1);
fill(v1.begin()+2, v1.end()?2,2);
fill_n(v1.begin()+4,2,3);
for_each(v1.begin(), v1.end(), myfunction);
return 0;
}
Program outputs:
A. none of these
B. 1 1 2 2 3 3 2 2 1 1
C. 1 1 2 2 2 2 2 2 1 1
D. compilation error
Answer: B