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NEW QUESTION: 1
Refer to the exhibit.
Link1 is a copper connection and Link2 is a fiber connection. The fiber port must be the primary port for all forwarding. The output of the show spanning-tree command on SW2 shows that the fiber port is blocked by spanning tree. An engineer enters the spanning- tree port-priority 32 command on GO/1 on SW2, but the port remains blocked. Which command should be entered on the ports that are connected to Link2 to resolve the issue?
A. Enter spanning-tree port-priority 64 on SW2.
B. Enter spanning-tree port-priority 32 on SW1.
C. Enter spanning-tree port-priority 224 on SW1.
D. Enter spanning-tree port-priority 4 on SW2.
Answer: B
Explanation:
Explanation
SW1 needs to block one of its ports to SW2 to avoid a bridging loop between the two switches.
Unfortunately, it blocked the fiber port Link2. But how does SW2 select its blocked port? Well, the answer is based on the BPDUs it receives from SW1. answer 'Enter spanning-tree port-priority 32 on SW1' BPDU is superior than another if it has:
1. answer 'Enter spanning-tree port-priority 32 on SW1' lower Root Bridge ID
2. answer 'Enter spanning-tree port-priority 32 on SW1' lower path cost to the Root
3. answer 'Enter spanning-tree port-priority 32 on SW1' lower Sending Bridge ID
4. answer 'Enter spanning-tree port-priority 32 on SW1' lower Sending Port ID These four parameters are examined in order. In this specific case, all the BPDUs sent by SW1 have the same Root Bridge ID, the same path cost to the Root and the same Sending Bridge ID.
The only parameter left to select the best one is the Sending Port ID (Port ID = port priority + port index). And the port index of Gi0/0 is lower than the port index of Gi0/1 so Link 1 has been chosen as the primary link.
Therefore we must change the port priority to change the primary link. The lower numerical value of port priority, the higher priority that port has. In other words, we must change the port-priority on Gi0/1 of SW1 (not on Gi0/1 of SW2) to a lower value than that of Gi0/0.
NEW QUESTION: 2
How can you protect CDP from reconnaissance attacks?
A. Enable dynamic ARP inspection on all untrusted ports.
B. Enable dot1x on all ports that are connected to other switches.
C. Disable CDP on trunk ports.
D. Disable CDP on ports connected to endpoints.
Answer: D
NEW QUESTION: 3
Solutions Architect에는 Amazon VPC에서 실행중인 멀티 레이어 애플리케이션이 있습니다. 애플리케이션에는 퍼블릭 서브넷의 프런트 엔드로 ELB Classic Load Balancer가 있고 프라이빗 서브넷에서 호스팅되는 두 개의 백엔드 Amazon EC2 인스턴스로 콘텐츠 기반 라우팅을 수행하는 Amazon EC2 기반 리버스 프록시가 있습니다. Architect는 엄청난 트래픽 증가를보고 리버스 프록시 및 현재 백엔드 설정이 불충분 할 것으로 우려합니다.
트래픽 수요에 맞게 애플리케이션을 자동으로 확장 할 수 있도록 비용 효율적인 솔루션을 달성하기 위해 Architect가 취해야 할 조치는 무엇입니까? (2 개 선택)
A. 프론트 엔드 및 리버스 프록시 계층을 ELB Application Load Balancer로 교체하십시오.
B. Amazon EC2 리버스 프록시 계층에 Auto Scaling을 추가하십시오.
C. 백엔드 집합에 t2 버스트 가능 인스턴스 유형을 사용하십시오.
D. Amazon EC2 리버스 프록시를 ELB 내부 Classic Load Balancer로 교체하십시오.
E. Amazon EC2 백엔드 집합에 Auto Scaling을 추가하십시오.
Answer: A,E
Explanation:
Explanation
Due to the reverse proxy being a bottleneck to scalability, we need to replace it with a solution that can perform content-based routing. This means we must use an ALB not a CLB as ALBs support path-based and host-based routing Auto Scaling should be added to the architecture so that the back end EC2 instances do not become a bottleneck. With Auto Scaling instances can be added and removed from the back end fleet as demand changes A Classic Load Balancer cannot perform content-based routing so cannot be used It is unknown how the reverse proxy can be scaled with Auto Scaling however using an ALB with content-based routing is a much better design as it scales automatically and is HA by default Burstable performance instances, which are T3 and T2 instances, are designed to provide a baseline level of CPU performance with the ability to burst to a higher level when required by your workload. CPU performance is not the constraint here and this would not be a cost-effective solution.
NEW QUESTION: 4
Which of the following SQL Server 2012 indexes stores data in a column-wise fashion instead of the traditional row-wise method?
A. Columnstore Index
B. Bitmap Index
C. Function-based Index
D. Clustered Index
Answer: C
Explanation:
Explanation
References:
https://msdn.microsoft.com/en-us/library/gg492088%28v=sql.110%29.aspx