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NEW QUESTION: 1
Refer to the exhibit that shows a demand matrix, a network topology with candidate links (in thick bluelinesand dashed lines), the definednetwork in thick blue lines and the demand routing (colored numbers in the figure). Every link is 80 km long. Which of the following requirements is supported by this network design with the displayed demand routing?
A. 1+1 protection
B. Minimum latency
C. Minimum cost design
D. Resilience against two link faults
Answer: A
NEW QUESTION: 2
An iteration takes place in a time frame with specific start and end dates, called a time-box. Which of the following is NOT an advantage of time-boxing?
A. Establishes a WIP limit
B. Forces prioritization
C. Demonstrates progress
D. Helps control technical debt
Answer: D
NEW QUESTION: 3
What benefit does using a working set in the IBM Domino Designer client allow?
A. It allows a designer to group all databases that are part of a project together so only they are showing in the Application Navigator.
B. In order to work on an application in the Domino Designer client, it must be in a working set.
C. It will prevent other designers from modifying applications while a developer is working with them in a working set.
D. It allows source control functionality to automatically track any changes to the databases in the working set.
Answer: A
NEW QUESTION: 4
Which statement is true regarding the UDP checksum?
A. It is computed based on the IP pseudo-header.
B. It is used for congestion control.
C. It cannot be all zeros.
D. It is used by some Internet worms to hide their propagation.
Answer: A
Explanation:
The method used to compute the checksum is defined in RFC 768:
"Checksum is the 16-bit one's complement of the one's complement sum of a pseudo header of information from the
IP header, the UDP header, and the data, padded with zero octets at the end (if necessary) to make a multiple of two
octets."
In other words, all 16-bit words are summed using one's complement arithmetic. Add the 16-bit values up. Each time
a carry-out (17th bit) is produced, swing that bit around and add it back into the least significant bit. The sum is then
one's complemented to yield the value of the UDP checksum field.
If the checksum calculation results in the value zero (all 16 bits 0) it should be sent as the one's complement (all 1s).
Reference: http://en.wikipedia.org/wiki/User_Datagram_Protocol