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NEW QUESTION: 1
If ClusterXL Load Sharing is enabled with state synchronization enabled, what will happen if one member goes down?
A. The connections are dropped as Load Sharing does not support High Availability.
B. The processing of all connections handled by the faulty machine is dropped, so all connections need to be re-established through the other machine(s).
C. There is no state synchronization on Load Sharing, only on High Availability.
D. The processing of all connections handled by the faulty machine is immediately taken over by the other member(s).
Answer: D
NEW QUESTION: 2
You design a Business Intelligence (BI) solution by using SQL Server 2008. You develop a SQL Server 2008 Analysis Services (SSAS) project and use Microsoft Visual Source Safe (VSS) as the source control system. After making changes to the project, you check in the files to the VSS. Then, you deploy the project to a shared server for testing. Four new developers are assigned to work in parallel on the project. You need to ensure that the new developers can modify the most recent version of the project and test it without affecting the work of the existing developers. What should you do?
A. Set the Deployment mode of the project to Deploy Changes Only.
B. Deploy the project to a local server.
C. Increment the version number of the deployment server in build properties for each deployment.
D. Set the Deployment mode of the project to Deploy All.
Answer: B
NEW QUESTION: 3
You are a database developer of a Microsoft SQL Server 2012 database. You are designing a table that will store Customer data from different sources. The table will include a column that contains the CustomerID from the source system and a column that contains the SourceID. A sample of this data is as shown in the following table.
You need to ensure that the table has no duplicate CustomerID within a SourceID. You also need to ensure that the data in the table is in the order of SourceID and then CustomerID. Which Transact- SQL statement should you use?
A. CREATE TABLE Customer(SourceID int NOT NULL IDENTITY,CustomerID int NOT NULL IDENTITY,CustomerName varchar(255) NOT NULL);
B. CREATE TABLE Customer(SourceID int NOT NULL PRIMARY KEY CLUSTERED,CustomerID int NOT NULL UNIQUE,CustomerName varchar(255) NOT NULL);
C. CREATE TABLE Customer(SourceID int NOT NULL,CustomerID int NOT NULL PRIMARY KEY CLUSTERED,CustomerName varchar(255) NOT NULL);
D. CREATE TABLE Customer(SourceID int NOT NULL,CustomerID int NOT NULL,CustomerName varchar(255) NOT NULL,CONSTRAINT PK_Customer PRIMARY KEY CLUSTERED(SourceID, CustomerID));
Answer: D