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NEW QUESTION: 1
A customer explains that they have a very uniqueenvironment, whichthey believe is very different from any other company.
What should be communicated to the customer to determine ifhe isa good match for an IBM SmartCloud Application Performance Management solution?
A. Determine the components within their application environment that are not unique.
B. Ask if there is any application monitoring currently in place.
C. Draw a diagram that illustrates the aspects of the customer's environment that are unique.
D. Let the customer know that all environments are similar so there are no concerns.
Answer: C
NEW QUESTION: 2
아래의 데이터는 두 개의 다른 머신 센터와 두 개의 제품에서 수집되었습니다.
다음 중이 문제에 대한 선형 프로그래밍 공식의 일부는 무엇입니까?
A. 적용 대상 : A <O.
B. 최대화 : 컨트 리뷰 션> 4A + 5B.
C. 대상 : 4A + 5B <130.
D. 대상 : 2.5A + 4B <60.
Answer: D
Explanation:
The linear programming solution is subject to constraints on the availability of machine hours in both centers. For example, products A and B require 2.5 and 4 hours per unit, respectively, in Machine Center 1, but only 60 hours are available. Hence, the optimal production of A and B to the following constraint:
2.5 A + 4B < 60
NEW QUESTION: 3
You have an Exchange Server 2013 organization named adatum.com.
You have a database availability group (DAG) that contains four Exchange servers named Server1, Server2, Server3, and Server4. The file share witness is on a server named Share1.
The organization has two Send connectors. The Send connectors are configured as shown in the following table.
Users report that email sent to external recipients is not being received.
You discover that outbound email messages are queued on Server3 and Server4.
You need to ensure that all of the email messages queued on Server3 and Server4 are delivered to the Internet as quickly as possible.
What should you do?
A. Modify the cost of External2.
B. Disable External1.
C. Modify the list of source bridgehead servers of External2.
D. Modify the cost of External1.
Answer: B
Explanation:
Explanation/Reference:
Note:
In Microsoft Exchange Server 2013, a Send connector controls the flow of outbound messages to the receiving server.
When a message is to be delivered to a remote delivery group, a routing path must be determined for the message. Exchange 2013 uses the same logic as Exchange 2010 to select the routing path for a message:
Calculate the least-cost routing path by adding the cost of the IP site links that must be traversed to reach the destination. If the destination is a connector, the cost assigned to the address space is added to the cost to reach the selected connector. If multiple routing paths are possible, the routing path with the lowest aggregate cost is used; If more than one routing path has the same cost, the routing path with the least number of hops is used; If more than one routing path is still available, the name assigned to the AD sites before the destination is considered. The routing path where the AD site nearest the destination is lowest in alphanumeric order is used. If the site nearest the destination is the same for all routing paths being evaluated, an earlier site name is considered.