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NEW QUESTION: 1
A. CustNo
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
C. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo
F. CustNo = L.CustNo
G. CustNo IS NULL
H. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
J. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
K. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: H
Explanation:
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp
NEW QUESTION: 2
HOTSPOT
You have an Exchange Server 2013 organization that contains four servers. The servers are configured as shown in the following table.
You run Get-TransportConfig and receive the output shown in the exhibit. {Click the Exhibit button,)
Use the drop-down menus to select the answer choice that completes each statement.
Answer:
Explanation:
NEW QUESTION: 3
Hot Area:
Answer:
Explanation:
Explanation/Reference:
Gi0/0/0
Correct network topology is Topology 2
Use "show cdp neighbor" to check and determine the topology.
NEW QUESTION: 4
展示を参照してください。
エンジニアは、ネットワークパラメータが/ 24サブネット上のユーザーの無線LAN接続に対して有効であることを確認する必要があります。値を左から右のネットワークパラメータにドラッグアンドドロップします。すべての値が使用されるわけではありません。
Answer:
Explanation:
