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NEW QUESTION: 1
Refer to the exhibit. Host A pings interface S0/0 on router 3.
What is the TTL value for that ping?
New C_THR82_2305 Test Question
A. 0
B. 1
C. 2
D. 3
Answer: C
Explanation:
Explanation/Reference:
Explanation:
From the CCNA ICND2 Exam book: "Routers decrement the TTL by 1 every time they forward a packet; if a router decrements the TTL to 0, it throws away the packet. This prevents packets from rotating forever." I want to make it clear that before the router forwards a packet, the TTL is still remain the same. For example, in the topology above, pings to S0/1 and S0/0 of Router 2 have the same TTL.
The picture below shows TTL values for each interface of each router and for HostB. Notice that Host A initializes ICMP packet with a TTL of 255:
New C_THR82_2305 Test Question

NEW QUESTION: 2
Ann, a security administrator, has concerns regarding her company's wireless network. The network is open and available for visiting prospective clients in the conference room, but she notices that many more devices are connecting to the network than should be.
Which of the following would BEST alleviate Ann's concerns with minimum disturbance of current functionality for clients?
A. Enable MAC filtering on the wireless access point.
B. Configure WPA2 encryption on the wireless access point.
C. Disable SSID broadcasting.
D. Lower the antenna's broadcasting power.
Answer: D
Explanation:
Some access points include power level controls that allow you to reduce the amount of output provided if the signal is traveling too far.

NEW QUESTION: 3
In the equation 4Y - 3kX = 18, k is a constant and Y equals 42 when X equals 12.
What is the approximate value of X when Y equals 36?
A. 25.
B. 10.
C. 20.
D. 5.
E. 15.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
First, find the constant k. Plug in the numbers for X and Y, to receive 4 x 42 - 3k x 12 = 18 k = (18 - 168)/36 = -25/6.
Now, plug in the value of Y to receive: 4 x 36 - 3kX = 18 after a little math, X is equal to 10.08, therefore the approximate answer is 10.