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NEW QUESTION: 1
図のようにold_alter_tableは無効になっています。
mysql> SELECT @@ old_alter_table;
RANGEパーティション表について、次の文を検討してください。
mysql> ALTER TABLEはDROP PARTITION p1、p3を順序付けします。
この文を実行した結果はどうですか？
A. 同じ文に複数のパーティションを指定できないため、構文エラーが発生します。
B. いつでも1つのパーティションしか削除できないため、最初のパーティション（p1）だけが削除されます。
C. p1パーティションとp3パーティションのデータはすべて削除されますが、テーブル定義は変更されません。
D. p1パーティションとp3パーティションのすべてのデータが削除され、テーブル定義が変更されました。
Answer: C
NEW QUESTION: 2
クリックして各目標を展開します。 Azureポータルに接続するには、ブラウザーのアドレスバーに「https://portal.azure.com」と入力します。
すべてのタスクの実行が完了したら、[次へ]ボタンをクリックします。
[次へ]ボタンをクリックすると、ラボに戻ることはできません。残りの試験を完了する間、採点はバックグラウンドで行われます。
概観
試験の次のセクションはラボです。このセクションでは、ライブ環境で一連のタスクを実行します。ほとんどの機能はライブ環境と同じように使用できますが、一部の機能（コピーと貼り付け、外部のWebサイトに移動する機能など）は、設計上可能ではありません。
スコアリングは、ラボで述べられたタスクの実行結果に基づいています。つまり、タスクをどのように達成するかは関係ありません。タスクを正常に実行すると、そのタスクのクレジットを獲得できます。
ラボは個別に時間を計られておらず、この試験には、完了する必要のある複数のラボがある場合があります。各ラボを完了するのに必要なだけ時間を使用できます。ただし、時間を適切に管理して、指定された時間内にラボおよび試験の他のすべてのセクションを完了することができるようにする必要があります。
ラボ内の[次へ]ボタンをクリックして作品を送信すると、ラボに戻ることができなくなりますのでご注意ください。
ラボを開始するには
[次へ]ボタンをクリックしてラボを開始できます。
次の要件を満たすには、appgw1015という名前のアプリケーションゲートウェイをデプロイする必要があります。
* subnet0に接続されているAzure仮想マシンへの内部IPトラフィックの負荷を分散します。
* Azure仮想マシンに99,99％の可用性のサービスレベルアグリーメント（SLA）を提供します。
Azureポータルから何をすべきですか？
Answer:
Explanation:
See explanation below.
Explanation
Step 1:
Click New found on the upper left-hand corner of the Azure portal.
Step 2:
Select Networking and then select Application Gateway in the Featured list.
Step 3:
Enter these values for the application gateway:
appgw1015 - for the name of the application gateway.
SKU Size: Standard_V2
The new SKU [Standard_V2] offers autoscaling and other critical performance enhancements.
Step 4:
Accept the default values for the other settings and then click OK.
Step 5:
Click Choose a virtual network, and select subnet0.
References:
https://docs.microsoft.com/en-us/azure/application-gateway/application-gateway-create-gateway-portal
NEW QUESTION: 3
View the Exhibit and examine the structures of the employees and departments tables.
You want to update the employees table as follows:
-Update only those employees who work in Boston or Seattle (locations 2900 and 2700).
-Set department_id for these employees to the department_id corresponding to London (location_id
2100).
-Set the employees' salary in iocation_id 2100 to 1.1 times the average salary of their department.
-Set the employees' commission in iocation_id 2100 to 1.5 times the average commission of their department.
You issue the following command:
What is the outcome?
A. It generates an error because multiple columns (SALARY, COMMISSION) cannot be specified together in an update statement.
B. It generates an error because a subquery cannot have a join condition in an update statement.
C. It executes successfully but does not give the correct result.
D. It executes successfully and gives the correct result.
Answer: C
Explanation:
Explanation/Reference:
Not that employees is used both in the first line (UPDATE employees) and later (FROM employees, departments). This would not cause the correct output. Instead aliases should be use.
The following would be the correct query:
UPDATE employees a
SET department_id
(SELECT department_id
FROM departments
WHERE location_id = '2100'),
(salary, commission_pct)
(SELECT 1.1*AVG(salary), 1.5*AVG(commission_pct)
FROM employees b
WHERE a.department_id = b.department_id)
WHERE department_id IN
(SELECT department_id
FROM departments
WHERE location_id = 2900
OR location_id = 2700);
Reference: http://docs.oracle.com/database/121/SQLRF/statements_10008.htm#SQLRF01708
NEW QUESTION: 4
In a single channel architecture (SCA) WLAN system, 802.11n (HT) APs should not share an SSID with
802.11g (ERP) APs.
What is the reason for this recommendation?
A. Beacons from 802.11n APs use 40 MHz channels, while beacons from 802.11g APs use 20 MHz channels.
B. The additional beacon material in 802.11n beacons would confuse 802.11b/g client stations.
C. Client stations would see two different sets of AP capabilities as they roam between APs with the same BSSID.
D. The added range of 802.11n APs would cause additional co-channel interference.
Answer: C