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NEW QUESTION: 1
セキュリティ管理者として、Red Hat Enterprise Server 5.564ビットを実行しているサーバーを強化するように求められます。
このサーバーは、DNSおよびタイムサーバーとして使用されています。データベース、Webサーバー、またはプリントサーバーとしては使用されません。
サーバーへのワイヤレス接続はなく、印刷する必要もありません。
コマンドウィンドウは、ルートアクセスとともに提供されます。ルートアクセス権を持つセキュアシェルを介して接続されています。
コマンドのリストについてヘルプを照会できます。
指示:
関係のないサービスとプロセスを無効にしてオフにする必要があります。
サーバーセッションのクラッシュをシミュレートすることが可能です。シミュレーションはリセットできますが、サーバーを再起動することはできません。シミュレーションの初期状態に戻したい場合は、いつでも[すべてリセット]ボタンをクリックしてください。
Free 2V0-32.24 Practice
Free 2V0-32.24 Practice
Answer:
Explanation:
See the explanation below
Explanation
In Order to deactivate web services, database services and print service, we can do following things
1) deactivate its services
/etc/init.d/apache2 stop
/etc/init.d/mysqld stop
2) close ports for these services
Web Server
iptables -I INPUT -p tcp -m tcp --dport 443 -j REJECTservice iptables save Print Server iptables -I INPUT -p tcp -m tcp --dport 631 -j REJECTservice iptables save Database Server iptables -I INPUT -p tcp -m tcp --dport <<port umber>> -j REJECTservice iptables save
3) Kill the process any running for the same
ps -aef|grep mysql
kill -9 <<process id>>

NEW QUESTION: 2
ネットワークには、Server1とServer2という2つのHyper-Vサーバーが含まれています。 Server1にはWindows 2012 R2がインストールされています。 Server2にはWindows Server 2016がインストールされています。
VM1という仮想マシンのServer1からServer2へのライブマイグレーションを実行します。
Server2でVM1の実動チェックポイントを作成する必要があります。
シーケンスで実行するWindows PowerShellコマンドレットは3つありますか。 これに答えるには、適切なコマンドレットをアクションリストからアンサーエリアに移動し、正しい順序で並べ替えます。
Free 2V0-32.24 Practice
Answer:
Explanation:
Free 2V0-32.24 Practice
Explanation
Free 2V0-32.24 Practice
We need to update the VM Version to enable the Production Checkpoints feature.
Step 1: Stop-VM
The virtual machine should be shut down before upgrading it.
Step 2. Update-VMVersion
To upgrade the virtual machine configuration version by using Windows PowerShell, use the Update-VMVersion cmdlet.
Step 3: CheckPoint-VM
The Checkpoint-VM cmdlet creates a checkpoint of a virtual machine.
Note: There is no Upgrade-VMVersion cmdlet

NEW QUESTION: 3
In what way are 802.11 channels defined?
A. By a center frequency and channel width
B. By channel width alone
C. By a high frequency and channel width
D. By a low frequency and channel width
Answer: B